One end of a brass rod of length 2.0 m and cross section `1cm^2` is kept in steam at `100^@C` and the other end in ice at `0^@C`. The lateral surface of the rod is covered by heat insulator. Determine the amount of ice melting per minute. Thermal conductivity of brass is `110 W//m-K` and specific latent heat of fusion of ice is `80 cal//g`.

Explanation

To determine the amount of ice melting per minute when one end of a brass rod is kept in steam at 100°C and the other end in ice at 0°C, we can follow these steps:

### Step 1: Identify the given values
- Length of the brass rod (L) = 2.0 m
- Cross-sectional area (A) = 1 cm² = \(1 \times 10^{-4} \, m^2\)
- Temperature at one end (T1) = 100°C
- Temperature at the other end (T2) = 0°C
- Thermal conductivity of brass (k) = 110 W/m·K
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