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A clock with a metal pendulum beating se...

A clock with a metal pendulum beating seconds keeps correct time at `0^@C`. If it loses 12.5 s a day at `25^@C`, the coefficient of linear expansion of metal of pendulum is

Text Solution

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Loss or gain per day `=dT=(1)/(2)alphadtxx86400`
Since `T=86400s` for each day
At `15^@C`,`5=(1)/(2)alpha(t-15)xx86400`
At `30^@C`,`10=(1)/(2)alpha(30-t)xx86400`
`(30-t)/(t-15)=2implies3t=60^@Cimpliest=20^@C`
`alpha=(10)/((t-15)xx86400)=(10)/(5xx86400)=0.000023`
`2.3xx(10^-5^@)/(C)=2`
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