A cyclic process ABCA shown in the V-T diagram is performed with a constant mass of an ideal gas. Show the same process on a p-V diagram, In the figure, CA is parallel to the V-axis and BC is parallel to the T-axis.`
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Explanation

a. For line AB, V = aT and both V and T increase so the gas equation `PV = mu RT` in the light of above yields.
`P(aT) = mu RT`, i.e., `P = (mu R//a)` = constant, with V increasing. So in P-V diagram, line AB will be a straight line parallel to the V-axis (with V increasing)
b. For line BC, V = constant ant T decreasing, so, the gas equation `PV = mu RT` in the light above yeilds.
`P = (mu RT)/(constant)`, where `alpha` T with T decreasing
i.e., along line BC, P decreases with V = constant. So in P-V diagram, line BC will be a straight line parallel to the P-axis (with P decreasing). c. `P = (mu RT)/(v)`, where PV = constant with V decreasing
So in P-V curve line, CA will be a hyperbola (with P increasing).
The complete cycle on P - V diagram is shown in Fig.