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How much work is done on the steam when ...

How much work is done on the steam when 1.00 mol of water at `100^(@)C` boils and becomes 1.00 mole of steam at `100^(@)C` at 1.00 atm pressure? Assume the steam to behave as an ideal gas , determine the change in the internal energy of the material as it vapourizes.

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To solve the problem, we need to calculate the work done on the steam during the phase change from water to steam and the change in internal energy. Let's break it down step by step. ### Step 1: Understand the Problem We have 1 mole of water at 100°C that boils to become 1 mole of steam at the same temperature and pressure of 1 atm. We need to find the work done on the steam and the change in internal energy during this process. ### Step 2: Calculate the Work Done on the Steam The work done on the steam can be calculated using the formula: \[ W = -P \Delta V \] ...
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