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Two moles of helium gas(lambda=5//3) are...

Two moles of helium gas`(lambda=5//3)` are initially at temperature `27^@C` and occupy a volume of 20 litres. The gas is first expanded at constant pressure until the volume is doubled. Then it undergoes an adiabatic change until the temperature returns to its initial value.
(i) Sketch the process on a p-V diagram.
(ii) What are the final volume and pressure of the gas?
(iii) What is the work done by the gas ?

Text Solution

AI Generated Solution

To solve the problem step by step, let's break it down into parts as requested. ### Step 1: Initial Conditions We start with 2 moles of helium gas at a temperature of \(27^\circ C\) (which is \(300 K\)) occupying a volume of \(20 \text{ liters}\). ### Step 2: Convert Units Convert the volume from liters to cubic meters: \[ ...
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