The highest vacuum attained so far is of the order of `10^(-11)` mm of mercury. How many molecules are there in 1 cc of a vessel under such a high vacuum at `0^(@)C` ?

Explanation

To find the number of molecules in 1 cc of a vessel under a high vacuum of \(10^{-11}\) mm of mercury at \(0^\circ C\), we can follow these steps:

### Step 1: Convert Pressure from mmHg to SI Units
The pressure given is \(10^{-11}\) mmHg. We need to convert this to pascals (Pa).

1 mmHg is approximately equal to \(133.322\) Pa. Therefore, we can calculate the pressure in pascals as follows:
\[
P = 10^{-11} \, \text{mmHg} \times 133.322 \, \text{Pa/mmHg} = 1.33322 \times 10^{-9} \, \text{Pa}
...