The temperature of a gas consisting of rigid diatomic moleculoes is T = 300 K. Calculate the angular root-mean square velocity of a rotating molecules if its moment of inertia is ` I = 2.0 xx 10^(-40) kg m^(2)`.

Explanation

To calculate the angular root-mean square velocity of a rotating diatomic molecule at a temperature of 300 K with a moment of inertia of \( I = 2.0 \times 10^{-40} \, \text{kg m}^2 \), we can follow these steps:

### Step 1: Understand the Equipartition of Energy
According to the law of equipartition of energy, each degree of freedom contributes \(\frac{1}{2} k T\) to the average kinetic energy, where \(k\) is the Boltzmann constant and \(T\) is the temperature in Kelvin.

### Step 2: Identify Degrees of Freedom
For a diatomic molecule, there are:
- 3 translational degrees of freedom (movement in x, y, and z directions).
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