As a result of the isobaric heating by `DeltaT=72K`, one mole of a certain ideal gas obtain an amount of heat `Q=1.6kJ`. Find the work performed by the gas, the increment of its internal energy and `gamma`.

Explanation

To solve the problem step by step, we will follow the principles of thermodynamics related to an ideal gas undergoing isobaric heating.

### Step 1: Identify the Given Data
We are given:
- Change in temperature, \( \Delta T = 72 \, \text{K} \)
- Heat absorbed, \( Q = 1.6 \, \text{kJ} = 1600 \, \text{J} \)
- Number of moles, \( n = 1 \, \text{mol} \)

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