Home
Class 11
PHYSICS
Two containers of equal volume contain t...

Two containers of equal volume contain the same gas at pressure `P_(1)` and `P_(2)` and absolute temperature `T_(1)` and `T_(2)`, respectively. On joining the vessels, the gas reaches a common pressure `P` and common temperature `T`. The ratio `P//T` is equal to

A

`(P_(1))/(T_(1)) + (P_(2))/(T_(2))`

B

`(P_(1)T_(1) + P_(2) T_(2))/((T_(1) + T_(2))^(2))`

C

`(P_(1)T_(2) + P_(2) T_(2))/((T_(1) + T_(1))^(2))`

D

`(P_(1))/(2T_(1)) + (P_(2))/(2T_(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the ideal gas law and the concept of combining gases in two containers. Here’s a step-by-step breakdown of the solution: ### Step 1: Define the Variables Let: - Volume of each container = \( V \) - Pressure in the first container = \( P_1 \) - Temperature in the first container = \( T_1 \) - Pressure in the second container = \( P_2 \) - Temperature in the second container = \( T_2 \) ### Step 2: Calculate the Number of Moles in Each Container Using the ideal gas law \( PV = nRT \), we can express the number of moles in each container. For the first container: \[ n_1 = \frac{P_1 V}{R T_1} \] For the second container: \[ n_2 = \frac{P_2 V}{R T_2} \] ### Step 3: Total Number of Moles After Joining the Containers When the two containers are joined, the total volume becomes \( 2V \). The total number of moles after joining the containers is: \[ n = n_1 + n_2 = \frac{P_1 V}{R T_1} + \frac{P_2 V}{R T_2} \] ### Step 4: Express Total Number of Moles in Terms of Final Pressure and Temperature After joining, the total number of moles can also be expressed in terms of the final pressure \( P \) and temperature \( T \): \[ n = \frac{P (2V)}{R T} \] ### Step 5: Set the Two Expressions for Total Moles Equal Now we set the two expressions for \( n \) equal to each other: \[ \frac{P_1 V}{R T_1} + \frac{P_2 V}{R T_2} = \frac{P (2V)}{R T} \] ### Step 6: Cancel Common Terms We can cancel \( V \) and \( R \) from both sides: \[ \frac{P_1}{T_1} + \frac{P_2}{T_2} = \frac{2P}{T} \] ### Step 7: Rearranging to Find the Ratio \( \frac{P}{T} \) Rearranging the equation gives: \[ \frac{P}{T} = \frac{1}{2} \left( \frac{P_1}{T_1} + \frac{P_2}{T_2} \right) \] ### Final Result Thus, the ratio \( \frac{P}{T} \) is: \[ \frac{P}{T} = \frac{1}{2} \left( \frac{P_1}{T_1} + \frac{P_2}{T_2} \right) \]

To solve the problem, we will use the ideal gas law and the concept of combining gases in two containers. Here’s a step-by-step breakdown of the solution: ### Step 1: Define the Variables Let: - Volume of each container = \( V \) - Pressure in the first container = \( P_1 \) - Temperature in the first container = \( T_1 \) - Pressure in the second container = \( P_2 \) ...
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Corrects|29 Videos
  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise Assertion-Reasoning|6 Videos
  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|22 Videos
  • KINETIC THEORY OF GASES

    CENGAGE PHYSICS ENGLISH|Exercise Compression|2 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Single correct anwer type|14 Videos

Similar Questions

Explore conceptually related problems

Two vessels of volume (V_1) and (V_2) contain the same ideal gas. The pressures in the vessels are (P_1) and (P_2) and the temperatures are (T_1) and (T_2) respectively . The two vessels are now connected to each other through a narrow tube. Assuming that no heat is exchanged between the surrounding and the vessels, find the common pressure and temperature attained after the connection.

Two idential container joined by a small pipe initially contain the same gas at pressure p_(0) and absolute temperature T_(0) . One container is now maintained at the same temperature while the other is heated to 2T_(0) . The common pressure of the gas

An ideal gas has pressure P, volume V and temperature T. Select the correct option.

An ideal gas in a thermally insulated vessel at internal pressure =P_(1) , volume =V_(1) and absolute temperature =T_(1) expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P_(2), V_(2) and T_(2) respectively. For this expansion.

An ideal gas in a thermally insulated vessel at internal pressure =P_(1) , volume =V_(1) and absolute temperature =T_(1) expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P_(2), V_(2) and T_(2) respectively. For this expansion.

An ideal gas in a thermally insulated vessel at internal pressure = P_(1) , volume = V_(1) and absolute temperature = T_(1) expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P_(2), V_(2) and T_(2) , respectively. For this expansion.

Two identical containers joned by a small pipe initially contain the same gas at pressue p_(o) and abosolute temperature T_(o^.) One container is now mantained at the same temperature while the other is heated to 2T_(0^.) The commmon pressure of the gases will be

Two adiabatic containers have volumes V_(1) and V_(2) respectively. The first container has monoatomic gas at pressure p_(1) and temperature T_(1) . The second container has another monoatomic gas at pressure p_(2) and temperature T_(2) . When the two containers are connected by a narrow tube, the final temperature and pressure of the gases in the containers are P and T respectively. Then

Two cylinder having m_(1)g and m_(2)g of a gas at pressure P_(1) and P_(2) respectively are put in cummunication with each other, temperature remaining constant. The common pressure reached will be

A sample of an ideal gas occupies a volume V at pressure P and absolute temperature T. The masss of each molecule is m, then the density of the gas is

CENGAGE PHYSICS ENGLISH-KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS-Single Correct
  1. If the intermolecules forces vanish away, the volume occupied by the m...

    Text Solution

    |

  2. The expansion of an ideal gas of mass m at a constant pressure P is gi...

    Text Solution

    |

  3. Two containers of equal volume contain the same gas at pressure P(1) a...

    Text Solution

    |

  4. An ideal monatomic gas is confined in a cylinder by a spring-loaded pi...

    Text Solution

    |

  5. A box contains N molecules of a perfect gas at temperature T(1) and te...

    Text Solution

    |

  6. Match the column.

    Text Solution

    |

  7. An ideal gas is initially at temperature T and volume V. ITS volume is...

    Text Solution

    |

  8. The pressure of a gas filled in a closed vessel increase by 0.4% when ...

    Text Solution

    |

  9. Pressure versus temperature graph of an ideal gas of equal number of a...

    Text Solution

    |

  10. The capacity of a vessel is 3 L. It contains 6 g oxygen, 8 g nitrogen ...

    Text Solution

    |

  11. Two gases occupy two containers A and B then gas in A, of volume 0.10 ...

    Text Solution

    |

  12. A closed vessel contains 8 g of oxygen and 7 g of nitrogen. The total...

    Text Solution

    |

  13. Energy of all molecules of a monatomic gas having a volume V and press...

    Text Solution

    |

  14. Forty calories of heat is needed to raise the temperature of 1 mol of ...

    Text Solution

    |

  15. For a gas the differce between the two specific heat is 4150 J//kg K. ...

    Text Solution

    |

  16. The specific heat at constant volume for the monatomic argon is 0.075 ...

    Text Solution

    |

  17. The temperature of 5 mol of gas which was held at constant volume was ...

    Text Solution

    |

  18. A gas is heated at a constant pressure. The fraction of heat supplied ...

    Text Solution

    |

  19. A monatomic gas expands at constant pressure on heating. The percentag...

    Text Solution

    |

  20. The average degree of freedom per molecule for a gas is 6. The gas per...

    Text Solution

    |