An ideal gas is initially at temperature T and volume V. ITS volume is increased by `DeltaV` due to an increase in temperature `DeltaT`, pressure remaining constant. The quantity `delta = DeltaV//V DeltaT` varies with temperature as

Options

A.
B.
C.
D.

Answer

C

Explanation

c. From ideal gas equation
`PV = RT`
`P Delta T = R Delta T`
Dividing Eq. (ii) by Eq. (i), we get
`(Delta T)/(V) = (Delta T)/(T) implies (Delta V)/(V Delta T) = (1)/(T) = delta` (given)
`:. Delta = (1)/(T)`
So the graph between `delta` and `T` will be a rectangular hyperbola.