An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are `Q_1=5960J, Q_2=-5585J, Q_3=-2980J and Q_4=3645J`, respectively. The corresponding quantities of work involved are `W_1=2200J, W_2=-825J, W_3=-1100J and W_4` respectively.
(1) Find the value of `W_4`.
(2) What is the efficiency of the cycle

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the total heat (ΔQ) in the cycle
The total heat exchanged in the cycle is the sum of the heat involved in each step:

\[ \Delta Q = Q_1 + Q_2 + Q_3 + Q_4 \]
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