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If the ratio of specific heat of a gas a...

If the ratio of specific heat of a gas at constant pressure to that at constant volume is `gamma`, the change in internal energy of a mass of gas when the volume changes from V to 2V at constant pressure p is

A

`R // (gamma - 1)`

B

`pV`

C

`pV // (gamma - 1)`

D

`gamma pV // (gamma - 1)`

Text Solution

Verified by Experts

The correct Answer is:
C

c. `Delta U = n C_(v) Delta T`
Also, `(C_(P))/(C_(v)) = gamma`
Hence `(C_(P) - C_(V))/(C_(v)) = gamma`
`implies C_(V) = R//(gamma - 1)`
`Delta U = (nR)/(gamma - 1) Delta T = (p Delta V)/(gamma - 1) = (p(2 V - V))/(gamma - 1) = (pV)/(gamma - 1)`
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