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A gas is expanded from volume V(0) to 2V...

A gas is expanded from volume `V_(0)` to `2V_(0)` under three different processes. Process 1 is isobaric process 2 is isothermal and process 3 is adiabatic. Let `DeltaU_(1), DeltaU_(2)` and `DeltaU_(3)` be the change in internal energy of the gas in these three processes. Then

A

`Delta U_(1) gt Delta U_(2) gt Delta U_(3)`

B

`Delta U_(1) lt Delta U_(2) lt Delta U_(3)`

C

`Delta U_(2) lt Delta U_(1) lt Delta U_(3)`

D

`Delta U_(2) lt Delta U_(3) lt Delta U_(1)`

Text Solution

Verified by Experts

The correct Answer is:
A
a. Change in temperature in process 1 will be greater and in process 3 will be least.
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