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Figure. Shows the P-V diagram for a Carn...

Figure. Shows the `P-V` diagram for a Carnot cycle. In this diagram

A

curve `AB` represents isothemal process and `BC` adiabatic process

B

curve `AB` represents adiabatic process and `BC` isothermal process

C

curve `CD` represents isothermal process and `DA` adaibatic process

D

curve `CD` represent adiabatic process and `DA` isothermal process

Text Solution

Verified by Experts

The correct Answer is:
A, C

For an adiabatic process, `PV^( gamma)=` constant . Differentiating w.r.t. `V`, we get
`(d P)/( dV) V^( gamma)+ P gammaV^( gamma-1)=0`
or ` ( dP)/( dV) =-( gamma P)/(V)`
For isothermal process, `PV=` constant.
Hence,
`(dP)/( dV) =-(P)/(V)`
Now, `dP//dV` is the slope of the `(P-V)` graph. Thus, the slope of the `( P-V)` graph for an adiabatic process is `gamma` times that for an isothermal process. Hence, curves `BC` and `DA` both represent adaibatic process and curves `AB` and `CD` both represent isothermal process. Thus, the correct choices are `(a)` and `(c)`.
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