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StatementI: Work done by a gas in isothe...

StatementI: Work done by a gas in isothermal expansion is more than the work done by the gas in the same expansion adaibatically.
Statement II: Temperature remains constant in isothermal ecpansion but not in adiabatic expansion.

A

Statement I: is true, Statement II is true and Statement II is the correct explanation for Statement I.

B

Statement I: is true, Statement II is true and Statement II is NOT the correct explanation for Statement I.

C

Statement I is true, Statement II is false.

D

Statement I is false, Statement II is true.

Text Solution

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The correct Answer is:
To solve the question, we need to analyze both statements provided: **Statement I**: Work done by a gas in isothermal expansion is more than the work done by the gas in the same expansion adiabatically. **Statement II**: Temperature remains constant in isothermal expansion but not in adiabatic expansion. ### Step-by-Step Solution: 1. **Understanding Isothermal Expansion**: - In an isothermal process, the temperature of the gas remains constant. According to the ideal gas law, the relationship between pressure (P), volume (V), and temperature (T) is given by \(PV = nRT\). Since T is constant, if the volume increases, the pressure must decrease accordingly. - The work done (W) during an isothermal expansion can be calculated using the formula: \[ W = nRT \ln\left(\frac{V_f}{V_i}\right) \] - Here, \(V_f\) is the final volume and \(V_i\) is the initial volume. 2. **Understanding Adiabatic Expansion**: - In an adiabatic process, there is no heat exchange with the surroundings. The temperature of the gas changes as it expands. The relationship for an adiabatic process is given by \(PV^\gamma = \text{constant}\), where \(\gamma\) is the heat capacity ratio (C_p/C_v). - The work done during an adiabatic expansion can be calculated using the formula: \[ W = \frac{P_i V_i - P_f V_f}{\gamma - 1} \] - Here, \(P_i\) and \(P_f\) are the initial and final pressures, respectively. 3. **Comparing Work Done**: - In an isothermal expansion, the area under the PV curve (which represents work done) is larger than that in an adiabatic expansion for the same change in volume. - Therefore, **Statement I is true**: The work done in isothermal expansion is indeed greater than that in adiabatic expansion. 4. **Analyzing Statement II**: - By definition, in an isothermal process, the temperature remains constant throughout the expansion. In contrast, during an adiabatic expansion, the gas cools down as it does work on the surroundings, leading to a decrease in temperature. - Thus, **Statement II is also true**: Temperature remains constant in isothermal expansion but not in adiabatic expansion. 5. **Conclusion**: - Both statements are true, and Statement II correctly explains Statement I. Therefore, the correct option is that both statements are true and Statement II explains Statement I. ### Final Answer: Both Statement I and Statement II are true, and Statement II correctly explains Statement I. ---

To solve the question, we need to analyze both statements provided: **Statement I**: Work done by a gas in isothermal expansion is more than the work done by the gas in the same expansion adiabatically. **Statement II**: Temperature remains constant in isothermal expansion but not in adiabatic expansion. ### Step-by-Step Solution: ...
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