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The average translational energy and the...

The average translational energy and the rms speed of molecules in a sample of oxygen gas at `300K` are `6.21xx10^(-21)J` and `484m//s`, respectively. The corresponding values at `600K` are nearly (assuming ideal gas behaviour)

A

`12.42xx10^(-21)J, 968 m//s`

B

`8.78xx10^(-21)J, 684 m//s`

C

`6.21xx10^(-21)J, 968m//s`

D

`12.42xx10^(-21)J, 684m//s`

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To find the average translational energy and the RMS speed of molecules in a sample of oxygen gas at 600K, we can follow these steps: ### Step 1: Calculate the Average Translational Kinetic Energy at 600K The average translational kinetic energy (KE) of a gas is given by the formula: \[ KE = \frac{3}{2} k T \] where: - \( k \) is the Boltzmann constant, - \( T \) is the absolute temperature in Kelvin. Since we know that the average translational kinetic energy is directly proportional to the temperature, we can set up the ratio: \[ \frac{KE_2}{KE_1} = \frac{T_2}{T_1} \] Given: - \( KE_1 = 6.21 \times 10^{-21} \, J \) at \( T_1 = 300 \, K \) - \( T_2 = 600 \, K \) Substituting the values: \[ \frac{KE_2}{6.21 \times 10^{-21}} = \frac{600}{300} = 2 \] Thus, we find: \[ KE_2 = 2 \times 6.21 \times 10^{-21} = 12.42 \times 10^{-21} \, J \] ### Step 2: Calculate the RMS Speed at 600K The RMS speed (\( V_{rms} \)) is given by the formula: \[ V_{rms} = \sqrt{\frac{3RT}{M}} \] where: - \( R \) is the universal gas constant, - \( T \) is the absolute temperature, - \( M \) is the molar mass of the gas. Since \( V_{rms} \) is proportional to the square root of the temperature, we can set up the ratio: \[ \frac{V_{rms2}}{V_{rms1}} = \sqrt{\frac{T_2}{T_1}} \] Given: - \( V_{rms1} = 484 \, m/s \) at \( T_1 = 300 \, K \) - \( T_2 = 600 \, K \) Substituting the values: \[ \frac{V_{rms2}}{484} = \sqrt{\frac{600}{300}} = \sqrt{2} \] Thus, we find: \[ V_{rms2} = \sqrt{2} \times 484 \approx 1.414 \times 484 \approx 684 \, m/s \] ### Final Values At 600K: - Average Translational Kinetic Energy \( KE_2 \approx 12.42 \times 10^{-21} \, J \) - RMS Speed \( V_{rms2} \approx 684 \, m/s \) ### Summary The corresponding values at 600K are: - Average Translational Energy: \( 12.42 \times 10^{-21} \, J \) - RMS Speed: \( 684 \, m/s \) ---

To find the average translational energy and the RMS speed of molecules in a sample of oxygen gas at 600K, we can follow these steps: ### Step 1: Calculate the Average Translational Kinetic Energy at 600K The average translational kinetic energy (KE) of a gas is given by the formula: \[ KE = \frac{3}{2} k T \] ...
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