A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wavelength between 499 nm and 500 nm is `U_1`, between 999 nm and 1000 nm is `U_2` and between 1499 nm and 1500 nm is `U_3` Wien's constant `b=2.88xx10^6nm-K` Then

Options

A. `U_1=0`
B. `U_3=0`
C. `U_1gtU_2`
D. `U_2gtU_1`

Answer

D

Explanation

Wien's displacement law is
`lambda_(m)T=b` , (`b=`Wien's constant)
`lambda_(m)=(b)/(T)=(2.88xx10^(6)nm-K)/(2880K)`
`lambda=1000nm`
Energy distribution with wavelength will be as follows:

From the graph it is clear that
`U_(2)gtU_(1)` , (in fact `U_(2)` is maximum)