An ideal gas is initially at temperature T and volume V. ITS volume is increased by `DeltaV` due to an increase in temperature `DeltaT`, pressure remaining constant. The quantity `delta = DeltaV//V DeltaT` varies with temperature as

Options

A.
B.
C.
D.

Answer

C

Explanation

We know that `V//T=`constant
`(V+DeltaV)/(T+DeltaT)=(V)/(T)` or `VT=TDeltaV=VT+VDeltaT`
or `TDeltaV=VDeltaT` or `(DeltaV)/(VDeltaT)=(1)/(T)`
This is representeed by graph.