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Starting from the same initial conditions, an ideal gas expands from volume `V_(1) to V_(2)` in three different ways. The work done by the gas is `W_(1)` if he process is purely isothermal, `W_(2)` if purely isobaric and `W_(3)` if purely adiabatic. Then

A

`W_2gtW_1gtW_3`

B

`W_2gtW_3gtW_1`

C

`W_1gtW_2gtW_3`

D

`W_1gtW_3gtW_2`

Text Solution

Verified by Experts

The correct Answer is:
A
Work done is equal to area under the curve on `PV` diagram. `(a)` is the correct option.
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