In a given process on an ideal gas, dW = 0 and `dQ lt 0`. Then for the gas

Options

A. the temperature will decrease
B. the volume will increase
C. the pressure will remain constant
D. the temperature will increase

Answer

A

Explanation

From the first law of thermodynamics
`dQ=dU+dW`
Here `dW=0` (given)
`:. dQ=dU`
Noe since `dQlt0` (given)
`dQ` is negative `implies dU=-ve`
`implies dU` decreases `implies` Temperature decreases.
`:.` The correct option is (a).