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Two identical rods are connected between two containers. One of them is at `100^(@)`C. If rods are connected in paralle then the rate of melting of ice is `g_(1)gs^(-1)`. If they are connected in series then the rate is `g_(2)gs^(-1)`. The ratio `g_(2)//g_(1)` is

A

2

B

4

C

`1//2`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
D

`q_(1)=(K2A(100))/(l)`
`q_(2)=(A(100))/((l)/(k)+(l)/(k))=(KA(100))/(2l)`
`:. (q_(2))/(q_(1))=(KA(100))/(2l)xx(l)/(K2A(100))=(1)/(4)`
.
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