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An ideal gas is expanding such that PT^2...

An ideal gas is expanding such that `PT^2=constant.` The coefficient of volume expansion of the gas is-

A

`1/T`

B

`2/T`

C

`3/T`

D

`4/T`

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The correct Answer is:
To find the coefficient of volume expansion of an ideal gas expanding under the condition \( PT^2 = \text{constant} \), we can follow these steps: ### Step 1: Understand the relationship given We start with the relationship \( PT^2 = \text{constant} \). This implies that the product of pressure \( P \) and the square of the temperature \( T \) remains constant during the expansion of the gas. ### Step 2: Use the ideal gas law From the ideal gas law, we know that: \[ PV = nRT \] where \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the temperature. ### Step 3: Express pressure in terms of volume and temperature We can express pressure \( P \) in terms of volume \( V \) and temperature \( T \): \[ P = \frac{nRT}{V} \] ### Step 4: Substitute pressure into the given relationship Substituting this expression for \( P \) into the equation \( PT^2 = \text{constant} \): \[ \left(\frac{nRT}{V}\right)T^2 = \text{constant} \] This simplifies to: \[ \frac{nRT^3}{V} = \text{constant} \] ### Step 5: Rearranging the equation Rearranging gives us: \[ V = \frac{nRT^3}{\text{constant}} \] Let’s denote the constant as \( C \): \[ V = C nRT^3 \] ### Step 6: Differentiate volume with respect to temperature To find the coefficient of volume expansion \( \gamma \), we need to differentiate \( V \) with respect to \( T \): \[ \frac{dV}{dT} = C nR \cdot 3T^2 \] ### Step 7: Calculate the coefficient of volume expansion The coefficient of volume expansion \( \gamma \) is defined as: \[ \gamma = \frac{1}{V} \frac{dV}{dT} \] Substituting \( \frac{dV}{dT} \) and \( V \): \[ \gamma = \frac{C nR \cdot 3T^2}{C nRT^3} \] This simplifies to: \[ \gamma = \frac{3T^2}{T^3} = \frac{3}{T} \] ### Step 8: Conclusion Thus, the coefficient of volume expansion \( \gamma \) of the gas is: \[ \gamma = \frac{3}{T} \] ### Final Answer The correct answer is option 3: \( \frac{3}{T} \). ---

To find the coefficient of volume expansion of an ideal gas expanding under the condition \( PT^2 = \text{constant} \), we can follow these steps: ### Step 1: Understand the relationship given We start with the relationship \( PT^2 = \text{constant} \). This implies that the product of pressure \( P \) and the square of the temperature \( T \) remains constant during the expansion of the gas. ### Step 2: Use the ideal gas law From the ideal gas law, we know that: \[ ...
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