Home
Class 11
PHYSICS
A particle executes SHM with an amplitud...

A particle executes SHM with an amplitude of `10 cm` and frequency `2 Hz`, at `t = 0`, the particle is at point where potential energy and kinetic energy are same. Find the equation of displacement of particle.

Text Solution

AI Generated Solution

To find the equation of displacement of a particle executing Simple Harmonic Motion (SHM), we can follow these steps: ### Step 1: Identify the given parameters - Amplitude (A) = 10 cm = 0.1 m - Frequency (f) = 2 Hz ### Step 2: Calculate the angular frequency (ω) The angular frequency (ω) is given by the formula: ...
Promotional Banner

Topper's Solved these Questions

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Solved Example|15 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 4.1|23 Videos
  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger|11 Videos
  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger type|3 Videos

Similar Questions

Explore conceptually related problems

In SHM with amplitude a, the potential energy and kinetic energy are equal to each other as displacement

A particle executing SHM with an amplitude A. The displacement of the particle when its potential energy is half of its total energy is

A particle doing SHM having amplitude 5 cm, mass 0.5 kg and angular frequency 5 rad//s is at 1cm from mean position.Find potential energy and kinetic energy.

A particle of mass 0.10 kg executes SHM with an amplitude 0.05 m and frequency 20 vib/s. Its energy of oscillation is

When a particle executes SHM oscillates with a frequency v, then the kinetic energy of the particle

A particle of mass m executing SHM with amplitude A and angular frequency omega . The average value of the kinetic energy and potential energy over a period is

A particle executes SHM with an amplitude 8 cm and a frequency 4 Hz initially, in the positive direction , determine its displacement equation and the maximum velocity and acceleration.

A particle executing S.H.M. having amplitude 0.01 m and frequency 60 Hz. Determine maximum acceleration of particle.

A particle executes linear SHM with amplitude A and mean position is x=0. Determine position of the particle where potential energy of the particle is equal to its kinetic energy.

A particle executing simple harmonic motion has amplitude of 1 m and time period 2 s . At t = 0 , net force on the particle is zero. Find the equation of displacement of the particle.