The average power transmitted across a cross section by two sound waves moving in the same direction are equal. The wavelength of two sound waves are in the ratio of `1:2`, then find the ratio of their pressure amplitudes.

Explanation

To solve the problem step by step, we will follow these logical steps:

### Step 1: Understand the Given Information
We are given that the average power transmitted across a cross-section by two sound waves is equal. We also know that the wavelengths of the two sound waves are in the ratio of 1:2.

### Step 2: Relate Power and Intensity
Since the average power transmitted is the same for both waves, we can conclude that their intensities are also equal. This is because intensity (I) is defined as power (P) per unit area (A):
\[ I = \frac{P}{A} \]
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