Two sound sources are moving away from a stationary observer in opposite direction with velocities `V_1` and `V_2(V_1gtV_2)`. The frequency of both the sources is 900 Hz. `V_1` and `V_2` are both quite less than speed of sound, `V=300(m)/(s)`. Find the value of `(V_1-V_2)` so that beat frequency observed by observer is 9 Hz. (in m/s).

Explanation

To solve the problem, we need to find the value of \( (V_1 - V_2) \) such that the beat frequency observed by a stationary observer is 9 Hz. We will follow these steps:

### Step 1: Understand the Beat Frequency Concept
The beat frequency is the difference between the frequencies of two sound sources. If one source has a frequency \( f_1 \) and the other has a frequency \( f_2 \), then the beat frequency \( f_b \) is given by:
\[ f_b = |f_1 - f_2| \]
In this case, we want \( f_b = 9 \, \text{Hz} \).
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