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In an organ pipe (may be closed or open ...

In an organ pipe (may be closed or open ) of `99 cm` length standing wave is set up , whose equation is given by longitudinal displacement.

`xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t`where `y` is measured from the top of the tube in `metres` and `t "in" seconds` . Here `1 cm` is the end correction.
The air column is vibrating in

A

open - closed

B

closed - open

C

open - open

D

closed - closed

Text Solution

Verified by Experts

The correct Answer is:
A

`(0.1 mm) cos ( 2pi)/(0.8) ( y + 1 cm ) cos 2 pi 7 (400) t`
end correction is `1 cm`. So at `y = - 1 cm`.
`(0.1 mm) cos ( 2 pi)/(0.8) ( - 1 cm + 1 cm) = ( 0.1 mm) cos (0) =` Antinode
So upper end is open.
At lower end `y = 99 cm = 0.99 m`
`= (0.1 mm) cos ( 2 pi)/( 0.8) (0.99 + 0.01)`
` = 0.01 cos ( 5 pi)/(2) = 0 rArr` Node
So tube is open closed.
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