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Velocity of a particle varies as v=2t^3-...

Velocity of a particle varies as `v=2t^3-3t^2` in `(km)/(hr)` If `t=0` is taken at 12:00 noon
Q. Find the expression for the acceleration of the particle.

A

`3t^2+3t`

B

`6t(t-1)`

C

`6t^2+3t`

D

none

Text Solution

Verified by Experts

The correct Answer is:
B
`v=2t^2-3t^2`
`a=(dv)/(dt)=6^2-6t=6t(t_1)`
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