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For the stationary wave y=4sin((pix)/(15...

For the stationary wave `y=4sin((pix)/(15))cos(96pit)`, the distance between a node and the next antinode is

A

7.5

B

15

C

22.5

D

30

Text Solution

AI Generated Solution

The correct Answer is:
To find the distance between a node and the next antinode for the stationary wave given by the equation \( y = 4 \sin\left(\frac{\pi x}{15}\right) \cos(96 \pi t) \), we can follow these steps: ### Step 1: Identify the general form of the standing wave equation The general form of a standing wave can be expressed as: \[ y = A \sin\left(\frac{2\pi x}{\lambda}\right) \cos(2\pi ft) \] where \( A \) is the amplitude, \( \lambda \) is the wavelength, and \( f \) is the frequency. ### Step 2: Compare the given equation with the general form From the given equation \( y = 4 \sin\left(\frac{\pi x}{15}\right) \cos(96 \pi t) \), we can identify: - The term \( \sin\left(\frac{\pi x}{15}\right) \) corresponds to \( \sin\left(\frac{2\pi x}{\lambda}\right) \). - The term \( \cos(96 \pi t) \) corresponds to \( \cos(2\pi ft) \). ### Step 3: Determine the wavelength \( \lambda \) From the comparison: \[ \frac{2\pi}{\lambda} = \frac{\pi}{15} \] To find \( \lambda \), we can rearrange the equation: \[ \lambda = \frac{2\pi}{\frac{\pi}{15}} = 2 \times 15 = 30 \] ### Step 4: Calculate the distance between a node and the next antinode The distance between a node and the next antinode is given by: \[ \text{Distance} = \frac{\lambda}{4} \] Substituting the value of \( \lambda \): \[ \text{Distance} = \frac{30}{4} = 7.5 \] ### Conclusion Thus, the distance between a node and the next antinode is \( 7.5 \) meters.
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