The `Mw` of a oxide of an element is 44. The `Ew` of the element is 14. The atomic weight of the element is

Options

A. 14
B. 28
C. 42
D. 56

Explanation

To find the atomic weight of the element given the molecular weight of its oxide and its equivalent weight, we can follow these steps:

### Step 1: Understand the Given Information
We know:
- Molecular weight (Mw) of the oxide = 44 g/mol
- Equivalent weight (Ew) of the element = 14 g/equiv

### Step 2: Use the Formula for Equivalent Weight
The equivalent weight of an element can be expressed as:
\[ Ew = \frac{M}{n} \]
where:
- \(M\) = atomic weight of the element
- \(n\) = valency of the element

From this, we can rearrange the formula to find the atomic weight:
\[ M = Ew \times n \]

### Step 3: Analyze the Molecular Weight of the Oxide
Assuming the oxide is of the form \(M_nO_m\), we can express the molecular weight as:
\[ Mw = n \times M + m \times 16 \]
where \(16\) is the atomic weight of oxygen.

### Step 4: Set Up the Equation
For the oxide, let's assume it is \(MO\) (where \(n=1\) and \(m=1\)):
\[ Mw = M + 16 \]
Given \(Mw = 44\), we can write:
\[ M + 16 = 44 \]

### Step 5: Solve for Atomic Weight
Rearranging the equation gives:
\[ M = 44 - 16 \]
\[ M = 28 \]

### Step 6: Check the Valency
Now, we need to find the valency \(n\) using the equivalent weight:
\[ Ew = \frac{M}{n} \]
Substituting the values we have:
\[ 14 = \frac{28}{n} \]
From this, we can solve for \(n\):
\[ n = \frac{28}{14} = 2 \]

### Step 7: Conclusion
Thus, the atomic weight of the element is:
\[ \text{Atomic Weight} = 28 \]

### Final Answer
The atomic weight of the element is **28 g/mol**.