`2 L` of air formed `1915 mL` of ozonised air when passed through Brodio's apparatus. The volume of ozone formed is

Options

A. `85 mL`
B. `170 mL`
C. `225 mL`
D. `425=.5 mL`

Explanation

To solve the problem, we need to determine the volume of ozone formed when 2 liters of air is passed through Brodie's apparatus, which results in 1915 mL of ozonized air.

### Step-by-step Solution:

1. **Understand the Initial Conditions**:
- We have 2 liters of air.
- This air is converted into ozonized air, which measures 1915 mL.

2. **Convert Liters to Milliliters**:
- Since 1 liter = 1000 mL, we convert 2 liters of air to milliliters:
\[ 2 \text{ L} = 2000 \text{ mL} \]

3. **Calculate the Volume of Ozone Formed**:
- The volume of ozone formed can be calculated by subtracting the volume of ozonized air from the initial volume of air:
\[ \text{Volume of ozone} = \text{Initial volume of air} - \text{Volume of ozonized air} \]
- Substituting the values:
\[ \text{Volume of ozone} = 2000 \text{ mL} - 1915 \text{ mL} \]
- Performing the subtraction:
\[ \text{Volume of ozone} = 85 \text{ mL} \]

4. **Conclusion**:
- The volume of ozone formed is **85 mL**.

### Final Answer:
The volume of ozone formed is **85 mL**.