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What is the valency of an element of whi...

What is the valency of an element of which the eqivalent weight is 12 and the specific heat is 0.25?

A

1

B

2

C

3

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To find the valency of an element given its equivalent weight and specific heat, we can follow these steps: ### Step 1: Understand the relationship between equivalent weight and valency The equivalent weight (EW) of an element is related to its molar mass (M) and valency (n) by the formula: \[ \text{Equivalent Weight} = \frac{M}{n} \] From this, we can express valency as: \[ n = \frac{M}{\text{Equivalent Weight}} \] ### Step 2: Use Dulong-Petit Law According to Dulong-Petit Law, the relationship between specific heat (s) and molar mass (M) is given by: \[ s \cdot M = 6.4 \] From this, we can express molar mass as: \[ M = \frac{6.4}{s} \] ### Step 3: Substitute the specific heat value We are given that the specific heat (s) is 0.25. Substituting this value into the equation for molar mass: \[ M = \frac{6.4}{0.25} \] Calculating this gives: \[ M = 6.4 \div 0.25 = 25.6 \] ### Step 4: Substitute the molar mass into the valency formula Now we can substitute the molar mass back into the valency equation: \[ n = \frac{M}{\text{Equivalent Weight}} \] Substituting the values we have: \[ n = \frac{25.6}{12} \] ### Step 5: Calculate the valency Now, performing the calculation: \[ n = \frac{25.6}{12} \approx 2.13 \] Since valency must be a whole number, we round this to the nearest whole number: \[ n \approx 2 \] ### Conclusion Thus, the valency of the element is approximately 2. ---

To find the valency of an element given its equivalent weight and specific heat, we can follow these steps: ### Step 1: Understand the relationship between equivalent weight and valency The equivalent weight (EW) of an element is related to its molar mass (M) and valency (n) by the formula: \[ \text{Equivalent Weight} = \frac{M}{n} \] From this, we can express valency as: \[ n = \frac{M}{\text{Equivalent Weight}} \] ...
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