Home
Class 11
CHEMISTRY
Mole fraction of a solute in an aqueous ...

Mole fraction of a solute in an aqueous solution is 0.2. The molality of the solution will be

A

13.88

B

1.388

C

0.138

D

0.0138

Text Solution

AI Generated Solution

The correct Answer is:
To find the molality of a solution given the mole fraction of the solute, we can follow these steps: ### Step 1: Understand the Definitions - **Mole Fraction (X)**: The mole fraction of a component in a solution is the ratio of the number of moles of that component to the total number of moles of all components in the solution. - **Molality (m)**: Molality is defined as the number of moles of solute per kilogram of solvent. ### Step 2: Identify Given Values - The mole fraction of the solute (XB) is given as 0.2. ### Step 3: Calculate the Mole Fraction of the Solvent (XA) Using the relationship: \[ XA + XB = 1 \] We can find the mole fraction of the solvent (XA): \[ XA = 1 - XB = 1 - 0.2 = 0.8 \] ### Step 4: Determine the Molar Mass of the Solvent Since the solvent is water (H2O), we calculate its molar mass: - Molar mass of H2O = 2 (Hydrogen) + 16 (Oxygen) = 18 g/mol. ### Step 5: Use the Formula for Molality The formula for molality (m) in terms of mole fraction is: \[ m = \frac{XB \times 1000}{XA \times M_A} \] Where: - \( XB \) = mole fraction of solute = 0.2 - \( XA \) = mole fraction of solvent = 0.8 - \( M_A \) = molar mass of solvent = 18 g/mol ### Step 6: Substitute the Values into the Formula Now, substitute the known values into the formula: \[ m = \frac{0.2 \times 1000}{0.8 \times 18} \] ### Step 7: Calculate the Molality Calculating the numerator and denominator: - Numerator: \( 0.2 \times 1000 = 200 \) - Denominator: \( 0.8 \times 18 = 14.4 \) Now, divide: \[ m = \frac{200}{14.4} \approx 13.88 \, \text{mol/kg} \] ### Final Answer The molality of the solution is approximately **13.88 mol/kg**. ---

To find the molality of a solution given the mole fraction of the solute, we can follow these steps: ### Step 1: Understand the Definitions - **Mole Fraction (X)**: The mole fraction of a component in a solution is the ratio of the number of moles of that component to the total number of moles of all components in the solution. - **Molality (m)**: Molality is defined as the number of moles of solute per kilogram of solvent. ### Step 2: Identify Given Values - The mole fraction of the solute (XB) is given as 0.2. ...
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Assertion-Reasoning|10 Videos
  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Integers|13 Videos
  • SOME BASIC CONCEPTS AND MOLE CONCEPT

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Multiple Correct (Mole Concept In Solution)|15 Videos
  • S-BLOCK GROUP 2 - ALKALINE EARTH METALS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 5.1 Objective|2 Videos
  • STATES OF MATTER

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Ture False)|25 Videos

Similar Questions

Explore conceptually related problems

Mole fraction of urea in its aqueous solution is 0.2, them molality of the solution will be.

Mole fraction of solvent in an aqueous solution is 0.7. What is the molality of this solution in mol/kg?

Mole fraction of solute in aqueous solution of 30% NaOH.

Mole fraction fo solvent in an aqueous solution is 0.8. What is the molality of this solution in mol/kg?

If the mass percentage of urea in an aqueous solution is 20% then molality of the solution will be

Define mole fraction of a solute in a solution.

The mole fraction of a solute in a solutions is 0.1 . At 298K molarity of this solution is the same as its molality. Density of this solution at 298 K is 2.0 g cm^(-3) . The ratio of the molecular weights of the solute and solvent, (MW_("solute"))/(MW_("solvent")) is

Mole fraction of solvent in aqueous solution of NaOH having molality of 3 is

The mole fraction of methyl alcohol in an aqueous solution is 0.02. Calculate the molality of the solution.

The mole fraction of the solute in one molal aqueous solution is:

CENGAGE CHEMISTRY ENGLISH-SOME BASIC CONCEPTS AND MOLE CONCEPT-Exercises Single Correct
  1. The weight of 1 xx 10^22 molecules of CuSO4. 5H2O is:

    Text Solution

    |

  2. How many moles of O(2) will be liberated by one mole of CrO(5) is the ...

    Text Solution

    |

  3. BrO(3)^(ɵ) + 5Br^(ɵ) rarr Br(2) + 3 H(2) O IF 50 mL 0.1 M BrO(3)^(ɵ)...

    Text Solution

    |

  4. To 1 L of 1.0 M impure H(2)SO(4) sample, 1.0 M NaOH solution was added...

    Text Solution

    |

  5. The expression relating mole fraction of solute (chi(2)) and molarity ...

    Text Solution

    |

  6. At 100°C and 1 atm, if the density of liquid water is 1.0 g cm^(-3) an...

    Text Solution

    |

  7. Consider the ionisation of H(2) SO(4) as follow" H(2) SO(4) + 2H(2)P...

    Text Solution

    |

  8. Calculate the number of oxygen atoms requried to combine with 7.0 g of...

    Text Solution

    |

  9. 36.5% HCl has density has density equal to 1.20 g mL^(-1). The molarit...

    Text Solution

    |

  10. 10 mL of 1 M BaCl(2) solution & 5 mL 0.5 M K(2)SO(4) are mixed togethe...

    Text Solution

    |

  11. Mole fraction of a solute in an aqueous solution is 0.2. The molality ...

    Text Solution

    |

  12. An excess of NaOH was added to 100 mL of a FeCl(3) solution which give...

    Text Solution

    |

  13. Two samples of HCl of 1.0 M and 0.25 M are mixed. Find volumes of thes...

    Text Solution

    |

  14. If 100 mL of H(2) SO(4) and 100 mL of H(2)O are mixed, the mass percen...

    Text Solution

    |

  15. 12.5 mL of a solution containing 6.0 g of a dibasic acid in 1 L was fo...

    Text Solution

    |

  16. One litre of a sample of hard water contains 5.55 mg of CaCl(2) and 4....

    Text Solution

    |

  17. 10 mL of 0.2 N HCl and 30 mL of 0.1 N HCl to gether exaclty neutralise...

    Text Solution

    |

  18. A metal oxide has the formul Z(2)O(3). It can be reduced by hydrogen t...

    Text Solution

    |

  19. The reaction between yttrium metal and dilute HCl produces H(2) (g) an...

    Text Solution

    |

  20. What volume of H(2) at 273 K and 1 atm will be consumed in obtaining 2...

    Text Solution

    |