The reaction between yttrium metal and dilute `HCl` produces `H_(2) (g)` and `Y^(3+)` ions. The molar ratio of yttrium to that hydrogen produced is

Options

A. `2 : 3`
B. `3 : 2`
C. ` 1 : 2`
D. `2 : 1`

Explanation

To find the molar ratio of yttrium (Y) to hydrogen gas (H₂) produced in the reaction with dilute hydrochloric acid (HCl), we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between yttrium metal and dilute hydrochloric acid can be represented as:

\[ \text{Y} + \text{HCl} \rightarrow \text{YCl}_3 + \text{H}_2 \]

### Step 2: Balance the chemical equation
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. Yttrium (Y) appears as 1 on both sides.
2. For chlorine (Cl), since YCl₃ contains 3 Cl atoms, we need 3 HCl.
3. Hydrogen (H) from HCl will produce H₂ gas.

The balanced equation becomes:

\[ 2\text{Y} + 6\text{HCl} \rightarrow 2\text{YCl}_3 + 3\text{H}_2 \]

### Step 3: Identify the molar ratio
From the balanced equation, we can see that:

- 2 moles of yttrium (Y) produce 3 moles of hydrogen gas (H₂).

### Step 4: Write the molar ratio
Thus, the molar ratio of yttrium to hydrogen produced is:

\[ \text{Y} : \text{H}_2 = 2 : 3 \]

### Final Answer
The molar ratio of yttrium to hydrogen produced is **2:3**.

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