An isotope of `Ge'_(32)^(76)` is

Options

A. Ge`._(32)^(77)`
B. As`._(32)^(77)`
C. Se`._(32)^(77)`
D. Se`._(34)^(78)`

Explanation

To determine the isotope of germanium represented as \( \text{Ge}_{32}^{76} \), we need to understand the concept of isotopes and how they are defined.

### Step-by-Step Solution:

1. **Understanding Isotopes**:
- Isotopes are variants of a particular chemical element that have the same number of protons (atomic number) but different numbers of neutrons, which results in different mass numbers.

2. **Identify the Atomic Number**:
- For germanium (Ge), the atomic number is 32. This means that every isotope of germanium will have 32 protons.

3. **Identify the Mass Number**:
- The mass number of the given isotope is 76. The mass number is the sum of protons and neutrons in the nucleus of an atom.

4. **Finding Neutrons**:
- To find the number of neutrons in this isotope, we can use the formula:
\[ \text{Number of Neutrons} = \text{Mass Number} - \text{Atomic Number} \]
- Substituting the values:
\[ \text{Number of Neutrons} = 76 - 32 = 44 \]

5. **Conclusion**:
- The isotope of germanium \( \text{Ge}_{32}^{76} \) has 32 protons and 44 neutrons.

### Final Answer:
The isotope of germanium \( \text{Ge}_{32}^{76} \) is characterized by having an atomic number of 32 and a mass number of 76.

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