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At 100°C and 1 atm, if the density of li...

At 100°C and 1 atm, if the density of liquid water is `1.0 g cm^(-3)` and that of water vapour is 0.0006 gcm-3 , then the volume occupied by water molecules in 1 litre of steam at that temperature is:

A

`6 cm^(3)`

B

`60 cm^(3)`

C

`0.6 cm^(3)`

D

`0.06 cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
For water vapours, `P = 0.0006 g c c^(-1)`
`:. 0.0006 = ("Mass")/("Volume") = ("Mass")/(1000)`
`"Mass" = 1000 xx 0.0006 = 0.6 g`
The density of liquid water is `1 g c c^(-1)`
So, the volume occupied by water is
`("Mass")/("Density"0 = (0.6)/(1) = 0.6 cc`
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