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6.3 g of oxalic acid dihydrate have been...

6.3 g of oxalic acid dihydrate have been dissolved in water to obtain a 250 ml solution. How much volume of 0.1 N NaOH would be required to neutralize 10 mL of this solution ?

A

`40 mL`

B

`20 mL`

C

`10 mL`

D

`4 mL`

Text Solution

Verified by Experts

The correct Answer is:
A
The normality of oxalic acid dihydrate is
`(6.3)/(63) xx (1)/(250) xx 100 = 0.4`
`(Ew` for `(COOH))_(2) . 2H_(2)O` is 63]
`N_(1) V_(1)` (acid) `= N_(2) V_(2)` (base)
or `0.4 xx 10 = 0.1 xx V_(2)`
or `V_(2) = 40 mL`
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