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A sugar syrup of weight 214.2 g contains...

A sugar syrup of weight 214.2 g contains 34.2 g of sugar `(C_(12)H_(22)O_(11))`. Calculate (i) molal concentration (ii) mole fraction of sugar in the syrup.

Text Solution

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The correct Answer is:
A, B
Weight of solvent `= 214. 2 - 34.2 = 180 g`
`m = (W_(2) xx 1000)/(Mw_(2) xx W_(1)) = (34.2 xx 1000)/(342 xx 180) = 0.555`
b. `chi_(2) = (n_(1))/(n_(1) + n_(2)) = (34.2//342)/((180)/(18) + (34.2)/(342)) = 0.0099`
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