Balance the following reaction in acidic medium.
`CuS+NO_(3)^(ө)rarrcu^(2+)+S_(8)+NO`

Explanation

To balance the reaction `CuS + NO3^- → Cu^2+ + S8 + NO` in acidic medium, we can follow these steps:

### Step 1: Identify the oxidation and reduction half-reactions
The first step is to identify the oxidation and reduction processes in the reaction.

1. **Oxidation half-reaction**: Sulfur in CuS is oxidized from -2 (in CuS) to 0 (in S8).
\[
8 \text{S}^{2-} \rightarrow \text{S}_8 + 16 \text{e}^-
...