Sulphur has highest oxidation state in

Options

A. `SO_(2)`
B. `H_(2)SO_(4)`
C. `Na_(2)S_(4)O_(6)`
D. `Na_(2)S_(2)O_(3)`

Explanation

To determine the highest oxidation state of sulfur in the given compounds, we will analyze each compound one by one and calculate the oxidation state of sulfur (S) in each case.

### Step 1: Calculate the oxidation state of sulfur in SO2
1. **Identify the oxidation states of other elements**:
- Oxygen (O) has an oxidation state of -2.
2. **Set up the equation**:
- Let the oxidation state of sulfur be \( X \).
- The compound is neutral, so the sum of oxidation states must equal 0.
- The equation becomes:
\[ X + 2(-2) = 0 \]
3. **Solve for \( X \)**:
\[ X - 4 = 0 \implies X = +4 \]
4. **Conclusion**: The oxidation state of sulfur in SO2 is +4.

### Step 2: Calculate the oxidation state of sulfur in H2SO4
1. **Identify the oxidation states of other elements**:
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
2. **Set up the equation**:
- Let the oxidation state of sulfur be \( X \).
- The equation becomes:
\[ 2(+1) + X + 4(-2) = 0 \]
3. **Solve for \( X \)**:
\[ 2 + X - 8 = 0 \implies X - 6 = 0 \implies X = +6 \]
4. **Conclusion**: The oxidation state of sulfur in H2SO4 is +6.

### Step 3: Calculate the oxidation state of sulfur in Na2S4O6
1. **Identify the oxidation states of other elements**:
- Sodium (Na) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
2. **Set up the equation**:
- Let the oxidation state of sulfur be \( X \).
- The equation becomes:
\[ 2(+1) + 4X + 6(-2) = 0 \]
3. **Solve for \( X \)**:
\[ 2 + 4X - 12 = 0 \implies 4X - 10 = 0 \implies 4X = 10 \implies X = 2.5 \]
4. **Conclusion**: The oxidation state of sulfur in Na2S4O6 is +2.5.

### Step 4: Calculate the oxidation state of sulfur in Na2S2O3
1. **Identify the oxidation states of other elements**:
- Sodium (Na) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
2. **Set up the equation**:
- Let the oxidation state of sulfur be \( X \).
- The equation becomes:
\[ 2(+1) + 2X + 3(-2) = 0 \]
3. **Solve for \( X \)**:
\[ 2 + 2X - 6 = 0 \implies 2X - 4 = 0 \implies 2X = 4 \implies X = +2 \]
4. **Conclusion**: The oxidation state of sulfur in Na2S2O3 is +2.

### Final Conclusion
After calculating the oxidation states of sulfur in all four compounds:
- SO2: +4
- H2SO4: +6
- Na2S4O6: +2.5
- Na2S2O3: +2

The highest oxidation state of sulfur is in **H2SO4**, which is +6.

### Answer
The correct option is **H2SO4**.