The valancy of carbons is generally `4`, but its oxidation state may be `-4, -2, 0, +2, -1`, etc. In the compounds containing `C, H`, and `O`, the oxidation number of `C` is calculated as
Oxidation number of `C= (2n_(O)-n_(H))/(n_(C ))`
Where `n_(O), n_(H)` and `n_(C )` are the numbers of oxygen, hydrogen, and carbons, atoms, respectively.
Teh oxidation of `C` in diamonds is

Options

A. `0`
B. `+1`
C. `-1`
D. `+2`

Explanation

To determine the oxidation state of carbon in diamonds, we can follow these steps:

### Step 1: Understand the Concept of Oxidation State
The oxidation state (or oxidation number) of an element in a compound indicates the degree of oxidation (loss of electrons) of that element. The oxidation state can vary based on the compound it is in.

### Step 2: Identify the Form of Carbon in Diamonds
Diamonds are a form of carbon. In chemistry, elements in their pure or elemental form have an oxidation state of zero.

### Step 3: State the Oxidation State of Carbon in Diamonds
Since diamonds are composed entirely of carbon atoms in their elemental form, the oxidation state of carbon in diamonds is 0.

### Conclusion
Thus, the oxidation state of carbon in diamonds is **0**.

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