Cartain materials such as turpentine oil, unsaturated organic compound, phosophorus, metals such as `Zn`, and `Pb`, etc., can absorb `O_(2)` from air in the presence of `H_(2)O`, which is converted to absorb `O_(2)` from air in the presence of `H_(2)O`, which is converted to `H_(2)O_(2)`. This is called autoxidation. Intermolecular redox reactions are those in which one molecule is oxidised and the other is reduced. Intramolecular redox reactions are those in which oen atom of a molecule is oxidised and the other atom is reduced.
Which of the following statements about the reaction is`//`are correct?
`2AsCl_(4)^(ө)+3Znrarr2Au+3Zn^(2+)+8Cl^(ө)`

Options

A. `AuCl_(4)^(ө)` is reduced to `Au`
B. `Zn` is oxidised to `Zn^(2+)`
C. `Cl^(ө)` is a spectator ion.
D. It is an intermolecular redox reaction.

Explanation

To determine the correctness of the statements regarding the reaction \( 2 \text{AsCl}_4^{\circ} + 3 \text{Zn} \rightarrow 2 \text{Au} + 3 \text{Zn}^{2+} + 8 \text{Cl}^{\circ} \), we will analyze the oxidation states of the elements involved and the nature of the reaction.

### Step-by-Step Solution:

1. **Identify Oxidation States**:
- For \( \text{AsCl}_4 \):
- Chlorine (\( \text{Cl} \)) has an oxidation state of -1.
- Therefore, in \( \text{AsCl}_4 \), the oxidation state of Arsenic (\( \text{As} \)) can be calculated as follows:
\[ x + 4(-1) = 0 \implies x - 4 = 0 \implies x = +4 \]
Thus, \( \text{As} \) is in the +4 oxidation state.
- For \( \text{Zn} \):
- Zinc (\( \text{Zn} \)) is in the elemental form, so its oxidation state is 0.
- For \( \text{Au} \):
- In the products, the oxidation state of \( \text{Au} \) is 0 (elemental form).
- For \( \text{Cl} \):
- In \( \text{ZnCl}_2 \), the oxidation state of \( \text{Cl} \) is -1.

2. **Determine Changes in Oxidation States**:
- \( \text{AsCl}_4 \) (As +4) is reduced to \( \text{Au} \) (Au 0), indicating that \( \text{As} \) is being reduced.
- \( \text{Zn} \) (Zn 0) is oxidized to \( \text{Zn}^{2+} \) (Zn +2).
- Therefore, \( \text{Zn} \) is oxidized while \( \text{AsCl}_4 \) is reduced.

3. **Identify Spectator Ions**:
- The \( \text{Cl}^- \) ions do not change their oxidation state during the reaction (remains -1 on both sides). Thus, they are spectator ions.

4. **Determine Reaction Type**:
- Since one species (Zn) is oxidized and another (AsCl4) is reduced, this is an intermolecular redox reaction.

### Conclusion:
Based on the analysis:
- **Statement A**: Correct (Au is reduced).
- **Statement B**: Correct (Zn is oxidized).
- **Statement C**: Correct (Cl- is a spectator ion).
- **Statement D**: Correct (it is an intermolecular redox reaction).

Thus, all statements A, B, C, and D are correct.

### Final Answer:
All of the statements (A, B, C, and D) are correct.

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