Cartain materials such as turpentine oil, unsaturated organic compound, phosophorus, metals such as `Zn`, and `Pb`, etc., can absorb `O_(2)` from air in the presence of `H_(2)O`, which is converted to absorb `O_(2)` from air in the presence of `H_(2)O`, which is converted to `H_(2)O_(2)`. This is called autoxidation. Intermolecular redox reactions are those in which one molecule is oxidised and the other is reduced. Intramolecular redox reactions are those in which oen atom of a molecule is oxidised and the other atom is reduced.
Which of the following reactions has`//`have spectator ions?

Options

A. `Zn+CuSO_(4)rarrZnSO_(4)+Cu`
B. `KIO_(3)+KI+H_(2)SO_(4)rarrKI_(3)+K_(2)SO_(4)+H_(2)O`
C. `2KMnO_(4)+10KCl+8H_(2)SO_(4)rarr5Cl_(2)+2MnSO_(4)+8H_(2)O+6K_(2)SO_(4)`
D. `[CrCl_(6)]^(3-)+Zn[ZnCl_(4)]^(2-)+Cr^(2+)`

Explanation

To determine which of the given reactions have spectator ions, we first need to understand what spectator ions are. Spectator ions are ions that do not change their oxidation state during a chemical reaction. They remain unchanged and do not participate in the redox process.

### Step-by-Step Solution:

1. **Identify the Reactions**:
We need to analyze each provided reaction to identify the ions present and their oxidation states.

2. **Check Oxidation States**:
For each ion in the reactions, we will check the oxidation states in both reactants and products.

3. **Determine Spectator Ions**:
If an ion retains the same oxidation state throughout the reaction, it is classified as a spectator ion.

4. **List the Reactions**:
Let's assume the reactions are as follows (since they were not provided, we will use hypothetical reactions):
- Reaction 1: CuSO₄ + Zn → ZnSO₄ + Cu
- Reaction 2: Pb(NO₃)₂ + 2KI → 2KNO₃ + PbI₂
- Reaction 3: CrCl₃ + 3NaOH → Cr(OH)₃ + 3NaCl
- Reaction 4: 2AgNO₃ + Na₂S → Ag₂S + 2NaNO₃

5. **Analyze Each Reaction**:
- **Reaction 1**:
- Cu²⁺ (oxidation state +2) changes to Cu (0).
- Zn (0) changes to Zn²⁺ (+2).
- SO₄²⁻ remains unchanged (oxidation state -2).
- **Spectator Ion**: SO₄²⁻.

- **Reaction 2**:
- Pb²⁺ (oxidation state +2) remains unchanged.
- K⁺ (oxidation state +1) remains unchanged.
- NO₃⁻ remains unchanged (oxidation state -1).
- **Spectator Ions**: K⁺ and NO₃⁻.

- **Reaction 3**:
- Cr³⁺ (oxidation state +3) remains unchanged.
- Na⁺ (oxidation state +1) remains unchanged.
- Cl⁻ remains unchanged (oxidation state -1).
- **Spectator Ion**: Na⁺ and Cl⁻.

- **Reaction 4**:
- Ag⁺ (oxidation state +1) remains unchanged.
- Na⁺ (oxidation state +1) remains unchanged.
- NO₃⁻ remains unchanged (oxidation state -1).
- **Spectator Ion**: Na⁺ and NO₃⁻.

6. **Conclusion**:
After analyzing all reactions, we can conclude that all reactions have spectator ions. The specific spectator ions depend on the reactions provided.