No reaction occurs in which of the following equations?

Options

A. `I^(ө)-Fe^(2+)rarr`
B. `F_(2)+2NaClrarr`
C. `Cl_(2)+2NaFrarr`
D. `I_(2)+2NaBrrarr`

Explanation

To determine in which of the given equations no reaction occurs, we will analyze each option based on the standard reduction potentials of the halogens and the reducing agents involved.

### Step-by-Step Solution:

1. **Understand the Order of Reduction Potentials:**
The standard reduction potentials for halogens are as follows:
- \( F_2 \) > \( Cl_2 \) > \( Br_2 \) > \( I_2 \)
This means that \( F_2 \) is the strongest oxidizing agent, and \( I_2 \) is the weakest.

2. **Analyze Each Option:**
- **Option A:** \( Fe + I^- \rightarrow Fe^{2+} + I_2 \)
- Here, \( Fe \) is a better reducing agent than \( I^- \). Since \( Fe \) can reduce \( I^- \) to \( I_2 \), this reaction will not occur as \( Fe \) cannot oxidize \( I^- \) effectively. **No reaction.**

- **Option B:** \( Fe + Cl_2 \rightarrow Fe^{2+} + Cl^- \)
- In this case, \( Cl_2 \) can oxidize \( Fe \) to \( Fe^{2+} \) and reduce itself to \( Cl^- \). This reaction is feasible. **Reaction occurs.**

- **Option C:** \( Cl_2 + 2NaF \rightarrow ? \)
- Here, \( Cl_2 \) cannot displace \( F^- \) because \( F_2 \) is a stronger oxidizing agent than \( Cl_2 \). Therefore, this reaction will not occur. **No reaction.**

- **Option D:** \( I_2 + Br^- \rightarrow ? \)
- In this case, \( I_2 \) cannot displace \( Br^- \) because \( Br_2 \) is a stronger oxidizing agent than \( I_2 \). Thus, this reaction will also not occur. **No reaction.**

3. **Conclusion:**
No reaction occurs in options A, C, and D.

### Final Answer:
No reaction occurs in:
- Option A: \( Fe + I^- \)
- Option C: \( Cl_2 + 2NaF \)
- Option D: \( I_2 + Br^- \)