The oxidation number of oxygen in `OF_(2)` is

Options

A. `+2`
B. `-2`
C. `+1`
D. `-1`

Explanation

To find the oxidation number of oxygen in the compound OF₂, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: We are given the compound OF₂, which consists of oxygen (O) and fluorine (F).

2. **Determine the Oxidation Number of Fluorine**: Fluorine is the most electronegative element and typically has an oxidation number of -1 in compounds.

3. **Set Up the Equation**: Since OF₂ is a neutral compound, the sum of the oxidation numbers must equal zero. Let the oxidation number of oxygen be represented as \( x \).

The equation can be set up as follows:
\[ x + 2(-1) = 0 \]

4. **Simplify the Equation**: Substitute the oxidation number of fluorine into the equation:
\[ x - 2 = 0 \]

5. **Solve for \( x \)**: Rearranging the equation gives:
\[ x = 2 \]

6. **Conclusion**: The oxidation number of oxygen in OF₂ is +2.

### Final Answer:
The oxidation number of oxygen in OF₂ is +2.