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The oxidation number of oxygen in OF(2) ...

The oxidation number of oxygen in `OF_(2)` is

A

`+2`

B

`-2`

C

`+1`

D

`-1`

Text Solution

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The correct Answer is:
To find the oxidation number of oxygen in the compound OF₂, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Compound**: We are given the compound OF₂, which consists of oxygen (O) and fluorine (F). 2. **Determine the Oxidation Number of Fluorine**: Fluorine is the most electronegative element and typically has an oxidation number of -1 in compounds. 3. **Set Up the Equation**: Since OF₂ is a neutral compound, the sum of the oxidation numbers must equal zero. Let the oxidation number of oxygen be represented as \( x \). The equation can be set up as follows: \[ x + 2(-1) = 0 \] 4. **Simplify the Equation**: Substitute the oxidation number of fluorine into the equation: \[ x - 2 = 0 \] 5. **Solve for \( x \)**: Rearranging the equation gives: \[ x = 2 \] 6. **Conclusion**: The oxidation number of oxygen in OF₂ is +2. ### Final Answer: The oxidation number of oxygen in OF₂ is +2.
To find the oxidation number of oxygen in the compound OF₂, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Compound**: We are given the compound OF₂, which consists of oxygen (O) and fluorine (F). 2. **Determine the Oxidation Number of Fluorine**: Fluorine is the most electronegative element and typically has an oxidation number of -1 in compounds. ...
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