The number of moles of `K_(2)Cr_(2)O_(7)` reduced by one mole of `Sn^(2+)` ions is

Options

A. `1//3`
B. `3`
C. `1//6`
D. `6`

Answer

A

Explanation

`(6e^(-)+Cr_(2)O_(7)^(2-)rarr2Cr^(3+))`
`Sn^(2+)rarrSn^(4+)+2e^(-)`
Equivalent of `Cr_(2)O_(7)^(2-)= "Equivalent of" Sn^(2+)`
`(n=6)` , `(n=2)`
`implies1 Eq= 1Eq`
`(1)/(6) mol =(1)/(2) mol`
`(1)/(3) "mol of" Cr_(2)O_(7)^(2-)= 1 "mol of" Sn^(2+)`.