The number of moles of `KMnO_(4)` reduced by `1 "mol of" KI` in alkaline medium is (a)1 / 5 (b)2 (c)3 / 2 (d)4

Options

A. `1`
B. `2`
C. `5`
D. `1//5`

Answer

B

Explanation

In a basic medium,
`3e^(-)+MnO_(4)^(ө)rarrMnO_(2)`
`I^(ө)rarrIO_(3)^(ө)+6e^(-)`
`underset((n=3))("Equivalent of "MnO_(4)^(ө))=underset((n=6))("Equivalent of" I^(ө))`
`1Eq=1Eq`
`(1)/(3) "mol"=(1)/(6)"mol"`
`(6)/(3)"mol of"MnO_(4)^(ө)= 1"mol of" I^(ө)`
`:. 2 "mol of" MnO_(4)^(ө) = 1"mol of"I^(ө)`