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In the reaction A^(+x) + MnO(4)^() to AO...

In the reaction `A^(+x) + MnO_(4)^() to AO_(3)^() + Mn^(++) +(1)/(2)O, ` if one mole fo `MnO_(4)^()` oxidises 1.67 moles of `A^(+x) ` to `AO_(3)^()` , then what will be the value of x ?

A

`5`

B

`3`

C

`2`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
C
`5e^(-)+MnO_(4)^(ө)rarrMn^(2+)`
`M^(x+)rarrMO_(3)^(ө)+(5-x)`
`x-6 = -1`
`x=5`
`"Equivalent of" MnO_(4)^(ө) = "Equivalent of" M^(x+)`
`1 mol xx 5= 1.67 mol xx (5-x)`
`:. X=2`
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