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aK(2)Cr(2)O(7)+bKCl+cH(2)SO(4) to xCrO(2...

`aK_(2)Cr_(2)O_(7)+bKCl+cH_(2)SO_(4) to xCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2)O`
The above equation balances when

A

`a=2, b=4,c=6 and x=2, y=6, z=3`

B

`a=4, b=2,c=6 and x=6,y=2,z=3`

C

`a=6,b=4,c=2 and x=6,y=3,z=2`

D

`a=1,b=4,c=6 and x=2,y=6,z=3`

Text Solution

Verified by Experts

The correct Answer is:
D
The balanced equation is
`K_(2)Cr_(2)O_(7)+4KCl+6H_(2)SO_(4)rarr2CrO_(2)Cl_(2)+6K_(2)SO_(4)+3H_(2)O`
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K_(2)Cr_(2)O_(7)+C_(2)O_(4)^(2-)+H_(2)SO_(4)rarr K_(2)SO_(4)+CO_(2)+Cr_(2)(SO_(4))_(3)+H_(2)O In above reaction, identify the elements which do not undergo change in their oxidation state :

Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)

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K_(2)Cr_(2)O_(7)+NaoH to CrO_(4)^(2-)

K_(2)Cr_(2)O_(7)+NaoH to CrO_(4)^(2-)

K_(2)Cr_(2)O_(7) overset(Delta) to K_(2)CrO_(4)+Cr_(2)O_(3)+O_(2)uarr

K_(2)Cr_(2)O_(7) overset(Delta) to K_(2)CrO_(4)+Cr_(2)O_(3)+O_(2)uarr

Taking the example of the reaction K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+FeSO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+Fe_(2)(SO_(4))_(3)+H_(2)O, explain how a redox reaction is balanced by oxidation number method.

Cr_(2)O_(7)^(2-)+H^(+)+SO_(3)^(2-) to Cr^(3+)(aq.)+SO_(4)^(2-)

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CENGAGE CHEMISTRY ENGLISH-REDOX REACTIONS-Exercises (Single Correct)
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  16. The number of electrons lost in the following change is Fe+H(2)Orarr...

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  17. The oxidation number of Pt in [Pt (C(2)H(4))Cl(3))"]"^(ө) is

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  18. The oxidation number of P in Mg(2)P(2)O(7) is

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  19. The oxidation number of phosphorus in PO(4)^(3-), P(4)O(10), and P(2)O...

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