The oxidation number of `Pr` in `Pr_(6)O_(11)` is

Options

A. `(22)/(6)`
B. `(20)/(6)`
C. `3`
D. `4`

Explanation

To find the oxidation number of Pr in the compound \( Pr_6O_{11} \), we can follow these steps:

### Step 1: Assign variables for oxidation states
Let the oxidation number of Pr be \( X \).

### Step 2: Identify the oxidation number of oxygen
The oxidation number of oxygen is typically \(-2\).

### Step 3: Set up the equation for the neutral compound
Since \( Pr_6O_{11} \) is a neutral compound, the sum of the oxidation states must equal zero. Therefore, we can write the equation:

\[ 6X + 11(-2) = 0 \]

### Step 4: Simplify the equation
This simplifies to:

\[ 6X - 22 = 0 \]

### Step 5: Solve for \( X \)
Now, we can solve for \( X \):

\[ 6X = 22 \]

\[ X = \frac{22}{6} \]

### Step 6: Simplify the fraction
We can simplify \( \frac{22}{6} \):

\[ X = \frac{11}{3} \]

### Conclusion
Thus, the oxidation number of Pr in \( Pr_6O_{11} \) is \( \frac{11}{3} \).

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