The oxidiant state of iodine in `H_(4)IO_(6)^(ө)` is

Options

A. `+7`
B. `-1`
C. `+5`
D. `+1`

Explanation

To determine the oxidation state of iodine in \( H_4IO_6^{-} \), we can follow these steps:

### Step 1: Assign Variables
Let the oxidation state of iodine (I) be \( x \).

### Step 2: Identify Known Oxidation States
- The oxidation state of hydrogen (H) is +1.
- The oxidation state of oxygen (O) is -2.

### Step 3: Write the Equation
Since the overall charge of the compound is -1, we can set up the following equation based on the sum of the oxidation states:

\[ \text{Sum of oxidation states} = \text{Charge} \]

This can be expressed as:

\[ 4(+1) + x + 6(-2) = -1 \]

### Step 4: Simplify the Equation
Now, simplify the left side of the equation:

\[ 4 + x - 12 = -1 \]

Combine like terms:

\[ x - 8 = -1 \]

### Step 5: Solve for \( x \)
Now, isolate \( x \):

\[ x = -1 + 8 \]
\[ x = +1 \]

### Conclusion
The oxidation state of iodine in \( H_4IO_6^{-} \) is +1.

### Final Answer
The oxidation state of iodine in \( H_4IO_6^{-} \) is +1.

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